Python Program to Check Leap Year

Python Program to Check Leap Year

Leap year program in python; Through this tutorial, you will learn how to check leap year program in python.

Python Program to Check Leap Year

1: Python program to check whether a given year is a leap year or not

  • Use a python input() function in your python program that allows the user to enter any year.
  • Next, use if statement to check whether the user entered year is Leap year or not. And store the result in a variable.
  • At the end of the program, print results.

1: Leap year program in python using if else:

# Python program to check the given year is leap or not

n = input("Please enter year")

year = int (n)

if (( year%400 == 0)or (( year%4 == 0 ) and ( year%100 != 0))):
    print("%d is a Leap Year" %year)
else:
    print("%d is Not the Leap Year" %year)

Output

Please enter year 2021 
2021 is Not the Leap Year 

2: Leap year program in python using elif:

  • Use a python input() function in your python program that allows the user to enter any year.
  • Next, use elif statement to check whether the user entered year is Leap year or not. And store the result in a variable.
  • At the end of the program, print results.
# Python program to check the given year is leap or not

n = input("Please enter year")

year = int (n)

if (year%400 == 0):
          print("%d is a Leap Year" %year)
elif (year%100 == 0):
          print("%d is Not the Leap Year" %year)
elif (year%4 == 0):
          print("%d is a Leap Year" %year)
else:
          print("%d is Not the Leap Year" %year)

Output

Please enter year 2020 
2020 is a leap year 

3: leap year program in python using nested if

  • Use a python input() function in your python program that allows the user to enter any year.
  • Next, use nested if statement to check whether the user entered year is Leap year or not. And store the result in a variable.
  • At the end of the program, print results.
# Python program to check the given year is leap or not

n = input("Please enter year")

year = int (n)

if (year % 4) == 0:
 if (year % 100) == 0:
   if (year % 400) == 0:
     print("{0} is a leap year".format(year))
   else:
     print("{0} is not a leap year".format(year))
 else:
   print("{0} is a leap year".format(year))
else:
 print("{0} is not a leap year".format(year))

Output

Please enter year 2020 
2020 is a leap year 

2: Python program to check leap year using function

  • Use a python input() function in your python program that allows the user to enter any year.
  • Next, import the math calendar module.
  • By using isleap() function of calendar module, To check whether the given year is a leap year or not.
  • After that, print the result.
# Python program to check the given year is leap or not 
# using math calender module in Python

#here import calender module
import calendar

n = input("Please enter year")

year = int (n)

# calling isleap() method to check for Leap Year
val = calendar.isleap(year)

if val == True: 
  print("% s is a Leap Year" % year)  
else:
  print("% s is not a Leap Year" % year)

Output

Please enter year 2019 
2019 is not a Leap Year  

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AuthorAdmin

My name is Devendra Dode. I am a full-stack developer, entrepreneur, and owner of Tutsmake.com. I like writing tutorials and tips that can help other developers. I share tutorials of PHP, Python, Javascript, JQuery, Laravel, Livewire, Codeigniter, Node JS, Express JS, Vue JS, Angular JS, React Js, MySQL, MongoDB, REST APIs, Windows, Xampp, Linux, Ubuntu, Amazon AWS, Composer, SEO, WordPress, SSL and Bootstrap from a starting stage. As well as demo example.

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