C Program for Simple Calculator

C Program for Simple Calculator

Simple calculator program in c; Through this tutorial, we will learn how to create simple calculator program in c programming language using switch case and if else statement.

Programs for Simple Calculator in C

  • C Program for Simple Calculator using Switch Case
  • C Program for Simple Calculator using If else

C Program for Simple Calculator using Switch Case

#include <stdio.h>
int main() {
  char op;
  double first, second;
  printf("Enter an operator (+, -, *, /): ");
  scanf("%c", &op);
  printf("Enter first numbers: ");
  scanf("%lf", &first);
  
  printf("Enter second numbers: ");
  scanf("%lf", &second);

  switch (op) {
    case '+':
      printf("%.1lf + %.1lf = %.1lf", first, second, first + second);
      break;
    case '-':
      printf("%.1lf - %.1lf = %.1lf", first, second, first - second);
      break;
    case '*':
      printf("%.1lf * %.1lf = %.1lf", first, second, first * second);
      break;
    case '/':
      printf("%.1lf / %.1lf = %.1lf", first, second, first / second);
      break;
    // operator doesn't match any case constant
    default:
      printf("Error! operator is not correct");
  }

  return 0;
}

The output of the above c program; as follows:

Enter an operator (+, -, *, /): +
Enter first numbers: 5
Enter second numbers: 2
5.0 + 2.0 = 7.0

C Program for Simple Calculator using If else

#include <stdio.h>
 
int main()
{
	char Operator;
	float num1, num2, result = 0;
	
	printf("\n Please Enter an Operator (+, -, *, /)  :  ");
  	scanf("%c", &Operator);
  	
	printf("\n Please Enter the Values for two Operands: num1 and num2  :  ");
  	scanf("%f%f", &num1, &num2);
  	
  	if(Operator == '+')
  	{
  		printf("\n The result of %.2f + %.2f  = %.2f", num1, num2, num1 + num2);
  	}
  	else if(Operator == '-')
  	{
  		printf("\n The result of %.2f - %.2f  = %.2f", num1, num2, num1 - num2);
  	}
  	else if(Operator == '*')
  	{
  		printf("\n The result of %.2f * %.2f  = %.2f", num1, num2, num1 * num2);
  	}
  	else if(Operator == '/')
  	{
  		printf("\n The result of %.2f / %.2f  = %.2f", num1, num2, num1 / num2);
  	}
  	else
  	{
  		printf("\n You have enetered an Invalid Operator ");
	}
	
  	return 0;
}

The output of the above c program; as follows:

Please Enter an Operator (+, -, *, /)  :  *
Please Enter the Values for two Operands: num1 and num2  :  5 2
The result of 5.00 * 2.00  = 10.00

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AuthorAdmin

My name is Devendra Dode. I am a full-stack developer, entrepreneur, and owner of Tutsmake.com. I like writing tutorials and tips that can help other developers. I share tutorials of PHP, Python, Javascript, JQuery, Laravel, Livewire, Codeigniter, Node JS, Express JS, Vue JS, Angular JS, React Js, MySQL, MongoDB, REST APIs, Windows, Xampp, Linux, Ubuntu, Amazon AWS, Composer, SEO, WordPress, SSL and Bootstrap from a starting stage. As well as demo example.

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